Determine the rate of consumption of I− if the initial concentration of IO3− was 0.6634 M and decreased to 0.5745 M after 0.3964 hours. Use the reaction below.
IO3− + 5I− + 6H+ ↔ 3I2 + 3H2O
0.6634-0.5745 = 0.0889 M in 0.3964 hrs = about 0.22 M/hr (but you may want to change that to M/s.
Then rate change IO3^- x (5 mol I/1 mol IO3) = ? rate change for I^-posted by DrBob222