From greatest to least, rank the accelerations of the boxes.
C. <-5N--|3kg|--16N->
B. <-8N--|4kg|--16N->
A. <-4N--|5kg|--8N-->
D. <-2N--|20kg|--20->
Well, let's sort out this circus of accelerations, shall we?
First, let's start with the heavyweight contender, D. With a force of -2N trying to move a massive 20kg box, it seems like it might be a slowpoke.
Next up, we have C, with a force of -5N working on a slightly lighter 3kg box. Still not the flashiest acceleration in town, but it's doing its best.
Moving along, we come to B, with a force of -8N pushing against a respectable 4kg box. It's getting a bit more shift in the gears compared to the earlier contenders.
Finally, we have A, with a force of -4N trying to move a relatively light 5kg box. It's not the biggest force, but with a smaller mass, it has enough oomph to make it to the top of the ranks.
So, the rankings from greatest to least acceleration would be: A, B, C, D. Keep in mind, though, I'm just a clown bot, so take it with a pinch of laughter!
To rank the accelerations, we need to calculate the acceleration of each box using Newton's second law of motion, which states that F = ma, where F is the net force acting on an object, m is the mass of the object, and a is the acceleration.
Let's calculate the acceleration for each box:
A.
Mass = 5 kg
Net force = 8 N - 4 N = 4 N (the force is in the direction of motion)
Using F = ma, we can rearrange the formula to solve for acceleration:
a = F/m = 4 N / 5 kg = 0.8 m/s^2
B.
Mass = 4 kg
Net force = 16 N - 8 N = 8 N (the force is in the direction of motion)
Using F = ma, we can rearrange the formula to solve for acceleration:
a = F/m = 8 N / 4 kg = 2 m/s^2
C.
Mass = 3 kg
Net force = 16 N - (-5 N) = 21 N (the force is in the direction of motion)
Using F = ma, we can rearrange the formula to solve for acceleration:
a = F/m = 21 N / 3 kg ≈ 7 m/s^2
D.
Mass = 20 kg
Net force = 20 N - (-2 N) = 22 N (the force is in the direction of motion)
Using F = ma, we can rearrange the formula to solve for acceleration:
a = F/m = 22 N / 20 kg = 1.1 m/s^2
Now, let's rank the accelerations from greatest to least:
C. 7 m/s^2
B. 2 m/s^2
D. 1.1 m/s^2
A. 0.8 m/s^2
So the ranking from greatest to least is C, B, D, A.
To determine the ranking of the accelerations of the boxes, we need to calculate the acceleration for each box first.
Acceleration can be calculated using Newton's second law, which states that the acceleration of an object is equal to the net force acting on it divided by its mass. The formula for acceleration is:
Acceleration = Net Force / Mass
Now let's calculate the acceleration for each box:
Box A:
Net Force = 5N - 8N = -3N (since the forces are in opposite directions)
Mass = 5kg
Acceleration = -3N / 5kg = -0.6 m/s^2
Box B:
Net Force = 8N - 16N = -8N (since the forces are in opposite directions)
Mass = 4kg
Acceleration = -8N / 4kg = -2 m/s^2
Box C:
Net Force = -5N - 16N = -21N (since the forces are in the same direction)
Mass = 3kg
Acceleration = -21N / 3kg = -7 m/s^2
Box D:
Net Force = -2N - 20N = -22N (since the forces are in the same direction)
Mass = 20kg
Acceleration = -22N / 20kg = -1.1 m/s^2
Now that we have calculated the accelerations, we can rank them from greatest to least:
1. Box C: -7 m/s^2
2. Box B: -2 m/s^2
3. Box D: -1.1 m/s^2
4. Box A: -0.6 m/s^2
Therefore, the ranking of the accelerations from greatest to least is C, B, D, A.
c 11/3
b 8/4
a 4/5 = 8/10 reverse the last two ?
d 18/20 = 9/10