a mixture of 10cm^3 of C5H12 and 0.084g of C12H24 was passed with an excess of oxygen. after cooling to room temperature, the reaidual gas was passed through aqueous potassium hydroxide. what volume was absorbed by the alkali
C5H12 + 8O2 ==> 5CO2 + 6H2O
C12H24 + 18O2 ==> 12CO2 + 12H2O
volume CO2 from pentane = 10cc x (5 mols CO2/1 mol C5H12) = 50 cc CO2.
mols dodecene = 0.084/molar mass = approx 5E-4. You should confirm ALL of these calculations since I've estimated here and there.
mols CO2 from dodecene = 5E-4 x (12 mols CO2/1 mol C12H24) = approx 6E-3.
volume CO2 from dodecene = 6E-3 x L/mol = ?
Total CO2 = L from pentane + L from dedecene.
NOTE. L/mol of a gas at room is 22.4 L at STP x (298/273) = ?
Hydrocloric acid se clorin
To find out the volume of gas absorbed by the alkali, you need to determine the difference in volume before and after passing through the aqueous potassium hydroxide.
Here are the steps you can follow to solve the problem:
1. Identify the balanced chemical equation for the reaction between the alkane (C5H12) and oxygen (O2) to form carbon dioxide (CO2) and water (H2O).
The balanced equation is:
C5H12 + 8O2 → 5CO2 + 6H2O
2. Calculate the number of moles of C12H24 used.
Given: mass of C12H24 = 0.084g
The molar mass of C12H24 can be calculated by adding the atomic masses of carbon (C) and hydrogen (H):
C12H24 = (12 × 12.01g/mol) + (24 × 1.01g/mol) = 156.32g/mol
Now, calculate the number of moles:
moles of C12H24 = mass / molar mass = 0.084g / 156.32g/mol
3. Calculate the number of moles of C5H12 used.
To do this, you need to convert the volume of C5H12 from cm^3 to liters (L).
1L = 1000cm^3
Given: volume of C5H12 = 10cm^3
volume of C5H12 in liters = 10cm^3 / 1000cm^3/L = 0.01L
Now, calculate moles:
moles of C5H12 = volume (in L) × molar concentration
moles of C5H12 = 0.01L × molar concentration
4. Determine the reactant in excess.
Compare the moles of C12H24 and C5H12 to find out which reactant is in excess. The one with fewer moles is the limiting reactant, while the other is in excess.
5. Calculate the number of moles of CO2 produced.
Based on the balanced equation in step 1, we know that 1 mole of C5H12 produces 5 moles of CO2.
Therefore, moles of CO2 = moles of C5H12 × 5
6. Calculate the volume of CO2 produced.
Since one mole of any gas occupies 22.4L at standard temperature and pressure (STP), you can calculate the volume of CO2 produced using the ideal gas law.
volume (in L) = moles × molar volume at STP (22.4L/mol)
7. Calculate the volume of gas absorbed by the alkali.
To find the volume of gas absorbed, subtract the volume of CO2 produced from the initial volume of the mixture.
volume of gas absorbed = initial volume - volume of CO2 produced
By following these steps and using the provided information, you should be able to calculate the volume of gas absorbed by the alkali.