Christian Brothers Brandy (80%, 1.7 L) what do I do with this problem it's a percent compostion work sheet

What's the problem?

I honestly don't know the teacher have us this worksheet that says percent compostion.

To solve this problem involving Christian Brothers Brandy with an 80% alcohol content, we can use the concept of percent composition. The problem states that you have a 1.7 L bottle of Christian Brothers Brandy.

The first step is to calculate the amount of alcohol in the given brandy.
1. Multiply the volume of the brandy (1.7 L) by the alcohol content percentage (80%):
Alcohol content = 1.7 L * 0.80 = 1.36 L

So, there is approximately 1.36 L of alcohol in the bottle of Christian Brothers Brandy.

Now, let's look at some possible ways to use this information on a percent composition worksheet:

1. Calculating the mass of alcohol:
- Look up the density of alcohol (ethanol) at room temperature (e.g., approximately 0.79 g/mL).
- Multiply the volume of alcohol (1.36 L) by the density of alcohol (0.79 g/mL) to get the mass:
Mass of alcohol = 1.36 L * 0.79 g/mL = 1.073 g

2. Comparing the mass of alcohol to the total mass:
- If you know the total mass of the brandy (e.g., provided in the problem), you can compare it to the calculated mass of alcohol (1.073 g). Calculate the percent composition by dividing the mass of alcohol by the total mass and multiplying by 100:
Percent composition of alcohol = (1.073 g / total mass) * 100%

3. Determining the volume of non-alcoholic components:
- If you want to find the volume of the non-alcoholic components in the brandy, subtract the volume of alcohol (1.36 L) from the total volume (1.7 L):
Volume of non-alcoholic components = 1.7 L - 1.36 L = 0.34 L

These are examples of how you can approach percent composition problems related to your bottle of Christian Brothers Brandy. Make sure to consider the specific requirements and formulas given in your worksheet.