I have 500 mL of a 6.0 M solution that I want diluted down to 2 M. How many mL of water should I add to the solutiion. " FOR EVERY PROBLEM YOU MUST DRAW A PICUTRE"
Can't draw pictures.
6.0M x 500 mL = 2M x ?mL
? mL is the total volume needed.
I tried and didn't get a accurate answer.
To solve this problem, we can use the dilution formula:
C1V1 = C2V2
Where:
C1 = Initial concentration (in this case, 6.0 M)
V1 = Initial volume (in this case, 500 mL)
C2 = Final concentration (in this case, 2.0 M)
V2 = Final volume (which we need to find)
To solve for V2, we rearrange the formula:
V2 = (C1V1) / C2
Substituting the given values:
V2 = (6.0 M * 500 mL) / 2.0 M
Now we can calculate it step by step:
V2 = (6.0 * 500) / 2.0
To simplify the calculation, we can start canceling out units:
V2 = (6 * 500) / 2
V2 = 3000 / 2
V2 = 1500 mL
Therefore, you will need to add 1500 mL of water to the 500 mL of the 6.0 M solution to obtain a 2.0 M solution.
I apologize, I am not able to draw a picture, but I hope this explanation helps you.