car traveling at 28.8 m/s hits a stone wall . The driver, who is wearing a shoulder harness and seat belt, moves forward 0.93 m as the car stops. Assuming his acceleration is uniform, find his average velocity during the collision. in m/S
average speed during constant acceleration = (end speed+start speed)/2
= (0 + 28.8)/2 = -14.4 m/s
Now if you want the average force for the next part of the qustion
F = d momentum/ d time
= - mass of driver (28.8) /(.93/-14.4)
G-Good job N-Naruto-kun
To find the average velocity during the collision, we need to first calculate the time it takes for the car to come to a stop.
We can use the equation of motion: v^2 = u^2 + 2as
Where:
v = final velocity (0 m/s, as the car comes to a stop)
u = initial velocity (28.8 m/s)
a = acceleration (which we need to find)
s = displacement (0.93 m)
Rearranging the equation, we have:
a = (v^2 - u^2) / (2s)
Substituting the given values, we can calculate the acceleration:
a = (0^2 - 28.8^2) / (2 * 0.93)
Now, we can find the time taken to stop the car using the equation:
v = u + at
Where:
v = final velocity (0 m/s)
u = initial velocity (28.8 m/s)
a = acceleration (which we just calculated)
t = time
Rearranging the equation, we have:
t = (v - u) / a
Substituting the given values, we can calculate the time taken to stop the car:
t = (0 - 28.8) / (-a)
Now, to find the average velocity during the collision, we can use the equation:
average velocity = displacement / time
Substituting the given values:
average velocity = 0.93 m / t
Finally, we can solve for the average velocity during the collision by substituting the previously calculated value of t into the equation and performing the calculation.