math

lim->
0

sin 3x/7x

i keep getting 0 even using the quotient rule but htis is not the answer

  1. 👍 0
  2. 👎 0
  3. 👁 97
asked by rudy
  1. the limit as x approaches 0 of (sinx/x) is 1. Hence, you need to get the given expression, sin3x/7x in the form sinu/u. Observe that sin3x/7x = (sin3x/3x)*(3x/7x)... multiply the numerator and denominator by 3x so we have the expression sinu/u. Thus, the limit as x approaches 0 of (sin3x/3x)*(3x/7x)is simply (1)*(3/7).

    You CANNOT use QUOTIENT rule since the question is asking for the VALUE of a particular LIMIT of a function, NOT the slope of the tangent at a particular point. You CAN use L'Hopital's Rule if you know what it is (I suggest you stick with the basics).

    1. 👍 0
    2. 👎 0
    posted by JP

Respond to this Question

First Name

Your Response

Similar Questions

  1. limit calc question

    2 questions!!! 1. Limit X approaching A (X^1/3-a^1/3)/ x-a 2. LiMIT x approaching 0 (1/3+x – 1/3) /x On the first, would it help to write the denominator (x-a) as the difference of two cubes ((x^1/3 cubed - a^1/3 cubed) second.

    asked by kev on March 2, 2007
  2. Calculus

    Can you please help me get the solution to this limit without using squeeze theorem and l'hopitals rule lim x to 0 of x^3 sin(1/x) lim x to 0 of x^2 sin^2(1/x)

    asked by Liv on January 11, 2017
  3. calculus

    using the squeeze theorem, find the limit as x->0 of x*e^[8sin(1/x)] what i did was: -1

    asked by Lid on October 27, 2015
  4. Calculus

    yes! tnk u ok? It's actually (x->0.) Find the limit of cot(x)-csc(x) as x approached 0? Lim [cot(x) - csc (x)] ..x->0 = Lim [(cos x -1)/sin x] ..x->0 Use L'Hopital's rule and take the ratio of the derivatives: Lim (-sin x/cos x) =

    asked by Maria on May 6, 2007
  5. Calculus

    Below are the 5 problems which I had trouble in. I can't seem to get the answer in the back of the book. Thanks for the help! lim (theta-pi/2)sec(theta) theta->pi/2 Answer: -1 I am not sure what to do here. lim

    asked by Anonymous on February 17, 2008
  6. calculus

    using L'Hospital's rule, evalutate; LIM as x->0 e^x +cos x / e^x + sin x I'm at LIM x->0 e^x+cosx / e^x +sinx but now I at a lost as to how to proceed.

    asked by redgy on November 21, 2011
  7. calc bc (condensed

    is the limit as x approaches 0 of sin3x over 3x equal to zero? sorry-- basically this is my problem: lim [sin 3x / 4x) x-> 0 ~~~~I multiplied& eventually got to .75* lim (sin 3x / 3x) x-> 0 ~so i figured since (lim (sinx/x) x-> 0

    asked by APpreciative student on September 14, 2010
  8. Calculus L'Hopital Rule

    lim x->0 (x)sin(x)/1-cos(x). They both go to 0 so 0/0. now take L'H and product rule of top? lim x->0 (1)sin(x)+ cos(x)(x)/1-cos(x) what next? how do i solve from here?

    asked by Greg on October 18, 2012
  9. Calculus

    L'Hospital's Rule Lim(lnx)^(x-1) x->1+ This is what I did so far... Form: 0^0 ln(lnx)/ (1/x-1) ----------------------------------- I am not sure if you could use L'Hospital Rule (as stated in the instruction)for the 2 problems

    asked by Anonymous on January 31, 2008
  10. Maths - Calculus

    Can anyone help with this...I need to find the derivative of the functions below. If possible please show working so I can try and understand? f(t) =3-t^4 and g(t)=sin(4t) Then using the Quotient Rule differentiate the function

    asked by Christine on February 13, 2011

More Similar Questions