I a 3 team league the teams play each other once per year.
Team A won 3 over a 2 year period.
Team B won 4 and Team C won 5
What is the probability of Team wining all two games next season
To calculate the probability of Team A winning both games in the next season, we need to understand the total number of possible outcomes for each game.
Given that there is a 3-team league and each team plays each other once per year, there will be a total of (3-1) games played per season (since each team plays the other two teams).
Since Team A will play two games in the next season, we have a total of 2 games to consider. In order for Team A to win both games, they need to win each game individually.
Looking at the previous results, we see that Team B won 4 games and Team C won 5 games over a 2-year period (which adds up to a total of 9 games). Therefore, the total possible outcomes for Team A winning each game are 9 (since they are the only team we are considering for winning both games).
To calculate the probability, we take the number of favorable outcomes (Team A winning both games, which is 1) and divide it by the total number of possible outcomes (which is 9):
Probability = (number of favorable outcomes) / (total number of possible outcomes)
= 1 / 9
Thus, the probability of Team A winning both games next season is 1/9 or approximately 0.1111 (11.11%).