What is the molarity of a solution with a volume of 974 mL containing 17 g of CuSO4?

mol CuSO4 = grams/molar mass

M = mols/L solution.

To find the molarity of a solution, you need to know the amount of the solute (in moles) and the volume of the solution (in liters). Here, we are given the volume of the solution in milliliters, so we need to convert it to liters.

1. Convert the volume of the solution from milliliters (mL) to liters (L):
974 mL ÷ 1000 = 0.974 L

Next, we need to find the number of moles of the solute (CuSO4).

2. Calculate the number of moles of CuSO4 using its molar mass:
Molar mass of CuSO4 = atomic mass of Cu + atomic mass of S + (4 x atomic mass of O)

The atomic masses are:
Cu = 63.55 g/mol
S = 32.06 g/mol
O = 16.00 g/mol

Molar mass of CuSO4 = 63.55 + 32.06 + (4 x 16.00) = 159.61 g/mol

Now, divide the mass of CuSO4 (17 g) by its molar mass:

Moles of CuSO4 = 17 g ÷ 159.61 g/mol

Finally, we can calculate the molarity.

3. Calculate the molarity (M) using the formula:
Molarity (M) = Moles of solute (mol) ÷ Volume of solution (L)

Molarity (M) = Moles of CuSO4 ÷ Volume of solution (L)
= (17 g ÷ 159.61 g/mol) ÷ 0.974 L

Calculate this expression to obtain the molarity of the solution.

It is important to note that in this calculation, you need to consider the significant figures and round the final answer to an appropriate number of decimal places based on the given data or the desired level of precision.