David and his father sat at the end of a see-saw 2 m from the pivot. where should David's mother sit in order to balance the see-saw
Force multiply by distance(1)+ force multiply by distance(2)= force multiply by distance(3)
400N multiply by 2m + 600d =700N multiply by 2m
800+600d=1400
600d=1400-800
600d=600
d=1m
400N multiply by 2m + 600d =700N multiply by 2m
800+600d=1400
600d=1400-800
600d=600
d=1m
Moment1=Moment2
Force1xDistance1=Force2xDistance2
(400Nx2m)+(600NxD)= 700Nx2m
800Nm+(600NxD)= 1400Nm
600NxD= 1400Nm-800Nm
600NxD= 600Nm
D= 600
➖➖➖ <-(600N upon 600Nm)
600
D= 1m ✔
Hard to say with that little information about masses.
To balance a see-saw, the moments on each side of the pivot need to be equal. The moment is calculated by multiplying the weight of an object by its distance from the pivot.
Let's assume that David's and his father's combined weight is W1 and his mother's weight is W2. Since David and his father are sitting 2 meters from the pivot, the moment on their side would be W1 × 2.
To balance the see-saw, the mother's moment on the other side of the pivot should be equal. Therefore, we need to find a distance X where David's mother should sit.
The equation to find the distance, X, can be written as:
W1 × 2 = W2 × X
From this equation, we can solve for X by rearranging it:
X = (W1 × 2) / W2
So, to balance the see-saw, David's mother should sit at a distance X from the pivot, which is given by the formula X = (W1 × 2) / W2.