Hi!! pls i need help!
1) Mg + Al2(So4)3
2)Fe + CuSO4
3)Mg + CuSO4
4)Zn + CuSO4
5)Mg + FeSO4
FOR ALL 5:
a)balanced eq
b)ionic equation
c) net ionic
Sure! I'd be happy to help you with those chemical reactions.
1) Mg + Al2(SO4)3
To balance the equation, first write down the reactants and products:
Mg + Al2(SO4)3 → MgSO4 + Al2(SO4)3
To balance the equation, make sure that the number of atoms of each element on both sides of the equation is the same. In this case:
Mg + Al2(SO4)3 → MgSO4 + Al2(SO4)3
The balanced equation is:
3Mg + Al2(SO4)3 → 3MgSO4 + 2Al(SO4)3
For the ionic equation, you need to separate the compounds into their respective ions:
3Mg + 2Al^3+ + 6SO4^2- → 3Mg^2+ + 6SO4^2- + 2Al^3+
To find the net ionic equation, cancel out the ions that appear on both sides:
3Mg + 2Al^3+ → 3Mg^2+ + 2Al^3+
2) Fe + CuSO4
The balanced equation is:
Fe + CuSO4 → FeSO4 + Cu
For the ionic equation:
Fe + Cu^2+ + SO4^2- → Fe^2+ + SO4^2- + Cu
The net ionic equation is:
Fe + Cu^2+ → Fe^2+ + Cu
3) Mg + CuSO4
Balanced equation:
Mg + CuSO4 → MgSO4 + Cu
Ionic equation:
Mg + Cu^2+ + SO4^2- → Mg^2+ + SO4^2- + Cu
Net ionic equation:
Mg + Cu^2+ → Mg^2+ + Cu
4) Zn + CuSO4
Balanced equation:
Zn + CuSO4 → ZnSO4 + Cu
Ionic equation:
Zn + Cu^2+ + SO4^2- → Zn^2+ + SO4^2- + Cu
Net ionic equation:
Zn + Cu^2+ → Zn^2+ + Cu
5) Mg + FeSO4
Balanced equation:
Mg + FeSO4 → MgSO4 + Fe
Ionic equation:
Mg + Fe^2+ + SO4^2- → Mg^2+ + SO4^2- + Fe
Net ionic equation:
Mg + Fe^2+ → Mg^2+ + Fe
Remember, to balance equations, you need to make sure that the number of atoms of each element on both sides of the equation is the same. The ionic equation separates the compounds into their respective ions, and the net ionic equation cancels out the ions that appear on both sides.
Sure! I can help you with that. Here are the step-by-step solutions for each of the reactions:
1) Mg + Al2(So4)3
a) To balance the equation, we need to ensure that the number of atoms on both sides is the same. The balanced equation is:
3 Mg + Al2(So4)3 -> 3 MgSo4 + 2 Al
b) The ionic equation shows the dissociation of compounds into ions in an aqueous solution. In this case, the ionic equation is:
3 Mg^2+(aq) + 2 Al3+(aq) + 3 So4^2-(aq) -> 3 MgSo4(s) + 2 Al(s)
c) The net ionic equation only includes the ions and molecules that undergo a change during the reaction. In this case, the net ionic equation is the same as the ionic equation since all ions take part in the reaction.
2) Fe + CuSO4
a) The balanced equation is:
Fe + CuSO4 -> FeSO4 + Cu
b) The ionic equation is:
Fe(s) + Cu^2+(aq) + SO4^2-(aq) -> FeSO4(aq) + Cu(s)
c) The net ionic equation is:
Fe(s) + Cu^2+(aq) -> Fe^2+(aq) + Cu(s)
3) Mg + CuSO4
a) The balanced equation is:
Mg + CuSO4 -> MgSO4 + Cu
b) The ionic equation is:
Mg(s) + Cu^2+(aq) + SO4^2-(aq) -> MgSO4(aq) + Cu(s)
c) The net ionic equation is:
Mg(s) + Cu^2+(aq) -> Mg^2+(aq) + Cu(s)
4) Zn + CuSO4
a) The balanced equation is:
Zn + CuSO4 -> ZnSO4 + Cu
b) The ionic equation is:
Zn(s) + Cu^2+(aq) + SO4^2-(aq) -> ZnSO4(aq) + Cu(s)
c) The net ionic equation is:
Zn(s) + Cu^2+(aq) -> Zn^2+(aq) + Cu(s)
5) Mg + FeSO4
a) The balanced equation is:
Mg + FeSO4 -> MgSO4 + Fe
b) The ionic equation is:
Mg(s) + Fe^2+(aq) + SO4^2-(aq) -> MgSO4(aq) + Fe(s)
c) The net ionic equation is:
Mg(s) + Fe^2+(aq) -> Mg^2+(aq) + Fe(s)
I hope this helps!
I will do the first one in detail. The others follow the same pattern.
Look up the activity series in your text/notes/Google/etc.
If the METAL is above the metal ION, the metal will displace it; otherwise, there is no reaction.
3Mg + Al2(SO4)3 --> 3MgSO4 + 2Al
Mg is ABOVE Al in the activity series; therefore, the ion is displaced. These are single replacement type reactions. Then I balanced the equation.
Turn the balanced equation into an total ionic equation. I will write (aq), (s), (l) after each to show it is a solid, aqueous, pure material (that's l).
3Mg(s) + 2Al^3+(aq) + 3SO4^2-(aq) ==> 3Mg^+2(aq) + 3SO4^2-(aq) + 2Al(s)
The net ionic equation is obtained by canceling anything that appears on both sides of the equation. Here the SO4^2-(aq) appears on both sides so the net ionic equation is
3Mg(s) + 2Al^3+(aq) ==> 3Mg^2+(aq) + 2Al(s)