I need help finding the derivative of
√3x/(x^2-4) at x=3
y = √(3x)/(x^2-4)
y' =
-√3(3x^2+4)
------------------
2√x (x^2-4)^2
At x=3 that is
-√3(31)/(2√3 (25)) = -31/50
√3x/(x^2-4) at x=3
y' =
-√3(3x^2+4)
------------------
2√x (x^2-4)^2
At x=3 that is
-√3(31)/(2√3 (25)) = -31/50