# Calculus

I need help finding the derivative of
√3x/(x^2-4) at x=3

1. 0
1. y = √(3x)/(x^2-4)

y' =

-√3(3x^2+4)
------------------
2√x (x^2-4)^2

At x=3 that is

-√3(31)/(2√3 (25)) = -31/50

posted by Steve

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