A basketball player makes 80% of her free throws. Recently during a very close game, she shot 5 free throws near the end of the game and missed 3 of them. The fans booed. What is the probability of her missing 3 (or more) free throws out of 5? Set up and conduct a simulation (using the random digits below) with 10 repetitions.
8323460278436012763012608726876805665109324646108127541745017491243217468017649817480716408712807408783402746237416207
48648148631085738
DO I USED THE NUMBERS 0 - 7 OR 1 - 8
0 1 2 3 4 5 6 7 OR 1 2 3 4 5 6 7 8
BELOW I USED 1-7 AND DID NOT USED ZERO HAS A FREE THROW
83234=MHHHH ALL HIT
60278=HMHHM MISS TWO
43601=HHHMH MISS ONE
27630=HHHHM MISS ONE
12608=HHHMM MISS TWO
72687=HHHMH HIT ALL
68056=HMMHH MISS ONE
6 5109=HHHMM MISS TWO
32464=HHHHH HIT ALL
61081=HHMMH MISS ONE
5 of 5 3
4 of 5 4
3 of 5 3
2 of 5 0
1 of 5
0 fo 5
Did you ever get this?
To calculate the probability of the basketball player missing 3 or more free throws out of 5, we need to count how many times she missed 3, 4, or all 5 free throws out of the 10 repetitions.
Looking at the simulated data, let's count the number of times she missed 3 or more free throws:
- In the first repetition, she missed 3 free throws.
- In the second repetition, she missed 2 free throws.
- In the third repetition, she missed 1 free throw.
- In the fourth repetition, she missed 1 free throw.
- In the fifth repetition, she missed 2 free throws.
- In the sixth repetition, she hit all free throws.
- In the seventh repetition, she missed 1 free throw.
- In the eighth repetition, she missed 2 free throws.
- In the ninth repetition, she hit all free throws.
- In the tenth repetition, she missed 1 free throw.
Out of the 10 repetitions, she missed 3 or more free throws in 5 of them.
To calculate the probability, we divide the number of repetitions where she missed 3 or more free throws (5) by the total number of repetitions (10):
Probability = Number of repetitions with 3 or more misses / Total number of repetitions
Probability = 5 / 10
Probability = 0.5 or 50%
Therefore, the probability of her missing 3 or more free throws out of 5 is 50%.