Graph the following equation and if possible, determine the slope.
y=-1
I know the slope is 0.
I know that one of the plots for the graph is (0,-1), but I need to know the other plot.
if you know that the slope is zero, then it is clear that the graph is a horizontal line through (0,-1).
To graph the equation y = -1, you only need two points since it is a horizontal line.
You already have one point, which is (0, -1). To find the other point, you can choose any x-value, as the y-value will always be -1.
For example, let's use x = 1. Then the coordinates of the other point would be (1, -1).
So, the graph of the equation y = -1 is a straight horizontal line passing through (0, -1) and (1, -1).
As for the slope, you correctly mentioned that the slope is 0. This is because the line is horizontal, and a horizontal line has a slope of 0.
To graph the equation y = -1, you need to plot points that satisfy this equation. In this case, any point that has a y-coordinate of -1 will work.
You correctly identified that one point on the graph is (0, -1). Now, let's find another point to complete the graph. To do that, we can choose any x-coordinate we like and substitute it into the equation y = -1 to find the corresponding y-coordinate.
For example, let's choose x = 1:
If we substitute x = 1 into the equation, we get y = -1. Therefore, the point (1, -1) lies on the graph.
With these two points, (0, -1) and (1, -1), you can plot them on a coordinate plane. Since the equation is y = -1, which is a horizontal line, these two points should appear on the same horizontal line at y = -1.
Regarding the slope, you are correct. The slope of any horizontal line is always 0. In this case, y = -1 is a horizontal line, so its slope is indeed 0.