Here are some multiple questions:

One out of every 5 "Choco-Delite" candy bars contains a 50 cents coupon. If Alex wants 15 coupons, how many candy should he buy?
a) 3 b) 20 c) 75 d) 100

What is the average of 10, 5, 3, 6, 14, 5, 6 and 7
a)7 b)8 c)56 d)9

16:4=20:___?
a)6 b)5 c)6 d)8

15Coupons * 5Candy bars/coupon=75 candy

bars.

Average = Sum/8

16/4 = 20/x.
Solve for X.

To answer the first question, we need to calculate the number of candy bars Alex should buy to get 15 coupons.

Given that one out of every five candy bars contains a 50 cents coupon, we can set up a proportion to solve for the number of candy bars.

Let's assign "x" as the total number of candy bars Alex needs to buy.

We can write the proportion as:

1/5 = 15/x

To solve for x, we can cross multiply:

1 * x = 5 * 15
x = 5 * 15
x = 75

Therefore, Alex should buy 75 candy bars.

So, the answer to the first question is c) 75.

To answer the second question, we need to calculate the average of the given set of numbers: 10, 5, 3, 6, 14, 5, 6, and 7.

To find the average, we sum up all the numbers and divide by the total count of numbers in the set.

Sum of the numbers = 10 + 5 + 3 + 6 + 14 + 5 + 6 + 7 = 56

Total count of numbers = 8

Average = sum of the numbers / total count of numbers = 56 / 8 = 7

Therefore, the answer to the second question is a) 7.

To answer the third question, we need to find the missing value in the given proportion:

16:4 = 20: ?

To solve for the missing value, we can use cross multiplication:

16 * ? = 4 * 20

Let's find the value of the missing term:

? = (4 * 20) / 16
? = 80 / 16
? = 5

Therefore, the missing value is 5.

Hence, the answer to the third question is b) 5.