Classify reaction as addition, displacement, or decomposition: Al(s)+NaOH(aq)=Al(OH)3(s)+Na+(aq)
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Displacement. The Sodium and Aluminum switched.
To classify the given reaction as addition, displacement, or decomposition, let's analyze the reactants and products involved.
In the given reaction: Al(s) + NaOH(aq) = Al(OH)3(s) + Na+(aq)
- Al(s) represents solid aluminum.
- NaOH(aq) represents aqueous sodium hydroxide.
- Al(OH)3(s) represents solid aluminum hydroxide.
- Na+(aq) represents aqueous sodium ion.
Based on the reactants and products, we can conclude that this reaction is a displacement reaction. This is because the aluminum atoms in the solid aluminum (Al) are displaced or replaced by the sodium ions (Na+) from the sodium hydroxide (NaOH). The displaced aluminum atoms then react with the hydroxide ions (OH-) from the sodium hydroxide to form solid aluminum hydroxide (Al(OH)3). Additionally, sodium ions (Na+) are released into the aqueous solution.
To classify this reaction, it is important to understand the types of chemical reactions. Addition reactions occur when two or more substances combine to form a single product. Decomposition reactions involve the breakdown of a single compound into two or more simpler substances. Displacement reactions occur when one element is displaced or replaced by another element in a compound.
In this case, since aluminum is displaced by sodium in the reaction, it can be classified as a displacement reaction.