3 similar shirts and 4 similar jackets cost $360. 1 such shirt and 3 such jackets cost $220. Find the cost of each shirt.
3s + 4j = 360
s + 3j = 220
Multiply second equation by 3, then subtract first from second.
3s + 9j = 660
5j = 300
Solve for j, then insert that value into either equation to find s.
EACH shirts cost $40
I was wondering if anyone would kindly answer my math related question. Here it goes: At the local clothing store,3 similar shirts and 4 similar jackets cost $360,and 1 shirt and 3 jackets cost $220. Find the cost of each shirt.
If you can,thank you. Please answer quickly,preferably in the next 10 minutes.
Dude, don't call people a loser!!!!
To solve this problem, we can assign variables to the unknowns and set up a system of equations based on the given information.
Let's assume the cost of each shirt is S and the cost of each jacket is J.
According to the first statement, 3 similar shirts and 4 similar jackets cost $360. Therefore, we can write the equation:
3S + 4J = 360 ----(Equation 1)
According to the second statement, 1 such shirt and 3 such jackets cost $220. Therefore, we can write the equation:
1S + 3J = 220 ----(Equation 2)
Now, we have a system of two equations with two variables. We can solve this system to find the values of S and J.
To do that, we can use the method of substitution or elimination. Let's use the substitution method here:
From Equation 2, we can solve for S:
S = 220 - 3J
Substitute the value of S in Equation 1:
3(220 - 3J) + 4J = 360
Distribute the multiplication:
660 - 9J + 4J = 360
Combine like terms:
-5J = 360 - 660
Simplify:
-5J = -300
Divide both sides by -5:
J = -300 / -5
J = 60
Substitute the value of J back into Equation 2 to find S:
S = 220 - 3(60)
S = 220 - 180
S = 40
Therefore, the cost of each shirt is $40.