Find the number of decibels of sound produced by a jet engine at a distance of 50 metres if the intensity is 10 watts per square metre.

This time I'll post the given formula too. Sorry to leave it out before!

The dB scale for measuring loudness, d, is given by the formula:
d=10log base 10(I X 10 to the power of 12) where I is the intensity of sound is watts per square metre.

Thanks for any help!

To find the number of decibels (dB) of sound produced by a jet engine at a distance of 50 meters, we can use the given formula:

d = 10 * log base 10(I * 10^12)

Given that the intensity (I) is 10 watts per square meter, we can substitute this value into the formula:

d = 10 * log base 10(10 * 10^12)

To evaluate this expression, follow these steps:

Step 1: Calculate the value inside the logarithm:
10 * 10^12 = 10,000,000,000,000

Step 2: Take the logarithm base 10 of the calculated value:
log base 10(10,000,000,000,000) ≈ 12

Step 3: Multiply the result by 10:
10 * 12 = 120

Therefore, the number of decibels of sound produced by the jet engine at a distance of 50 meters with an intensity of 10 watts per square meter is approximately 120 dB.