Question

If f(x)=x+4 and g(x)=x-4

a)Find an expression for (f*g)(x)?

b)what is the minimum value of the function (f*g)(x)

I used the * sign for a times symbol.

Answer 1

f*g = (x+4)(x-4) = x^2 -16

b) y = x^2 - 16
x^2 is always >/= 0
so smallest y is -16