Rectangle ABCD is similar to Rectangle EFGH.
If AB = 5 feet, BC = 12 feet, and FG = 25 feet, what is the length of EF
5 (25/12) = 125/12
5*25/12=125/10
what is s?
To solve this problem, let's use the concept of similar triangles.
Since rectangles ABCD and EFGH are similar, their corresponding sides are in proportion.
AB/EF = BC/FG
Plugging in the given values, we have:
5/EF = 12/25
To solve for EF, we can cross-multiply and then divide:
12 * EF = 5 * 25
12 * EF = 125
Dividing both sides by 12:
EF = 125/12
Hence, the length of EF is approximately 10.42 feet.