If you shook the end of a rope up and down 7 times each second, what would be the period of the waves set up in the rope? s

What would be the frequency? Hz

P = 1/7 s.

F = 1/P = 7 cycles/s = 7 Hz.

To determine the period and frequency of the waves set up in the rope, we need to understand the relationship between these two concepts.

The period of a wave is defined as the time it takes for a complete cycle or oscillation to occur. It is usually denoted by the symbol T and is measured in seconds (s).

The frequency of a wave, on the other hand, represents the number of complete cycles or oscillations that occur per unit of time. It is denoted by the symbol f and is measured in hertz (Hz).

The relationship between period and frequency is inverse. The frequency of a wave can be determined by taking the reciprocal of its period:

frequency (f) = 1 / period (T)

Now, given that you are shaking the end of the rope up and down 7 times each second, we can conclude that the frequency of the waves set up in the rope is 7 Hz. This is because for every second, 7 complete cycles or oscillations occur.

To find the period, we can use the reciprocal relationship between frequency and period:

period (T) = 1 / frequency (f)

In this case, the period would be:

period (T) = 1 / 7 Hz = 0.14 seconds (s)

Therefore, the period of the waves set up in the rope would be 0.14 seconds (s), and the frequency would be 7 Hz.