I am supposed to name this using IUPAC method for binary compounds (i think)
arsenic(111) sulfide
silicon tetraiodide
antimony (111)bromide
ammonia gas
lead(11)
and the things in the brackets are supposed to be the roman numerals
I don't get it. Aren't these the names? Perhaps you want the formula. By the way, the Stock system uses Roman numerals. You have used the number 1; you should use the capital i so it would look like this.
arsenic (III) sulfide.
etc.
As2S3 is #1 (known as arsenious sulfide in the old days.)
SiI4
SbBr3
NH3
Pb^2+
To name binary compounds using the IUPAC method, you need to determine the oxidation states of the elements involved.
1. Arsenic(III) sulfide: Arsenic has an oxidation state of +3, and sulfur has an oxidation state of -2. Therefore, the compound is named "Arsenic(III) sulfide".
2. Silicon tetraiodide: Silicon has an oxidation state of +4, and iodine has an oxidation state of -1. Therefore, the compound is named "Silicon tetraiodide".
3. Antimony(III) bromide: Antimony has an oxidation state of +3, and bromine has an oxidation state of -1. Therefore, the compound is named "Antimony(III) bromide".
4. Ammonia gas: Ammonia is a covalent compound, and it does not require oxidation state naming. Therefore, it is simply named "Ammonia gas".
5. Lead(II): Lead is a metal that can have multiple oxidation states. In this case, "Lead(II)" indicates the oxidation state of lead as +2.
Remember to always check the oxidation states and use the appropriate rules when naming compounds.