(4b+5c)(4c+3b)=
16bc+12b(squared)+20c(squared)+15bc
12b(squared)+ 20c (squared)+ 31bc
(4b+5c)(4c+3b) = (4b+5c)(3b+4c)
4b + 5c
3b + 4c
Multiplying
16bc+20C^2
12b^2+15bc
= 12b^2+31bc+20c^2
I hope this makes the process clearer. Thanks for asking.
To simplify the given expression (4b+5c)(4c+3b), we can use the distributive property.
Step 1: Multiply the first term of the first parentheses (4b) by both terms in the second parentheses (4c and 3b).
(4b) * (4c) = 16bc
(4b) * (3b) = 12b^2
Step 2: Multiply the second term of the first parentheses (5c) by both terms in the second parentheses (4c and 3b).
(5c) * (4c) = 20c^2
(5c) * (3b) = 15bc
Step 3: Combine the results from Steps 1 and 2:
16bc + 12b^2 + 20c^2 + 15bc
Step 4: Simplify the expression by combining like terms:
16bc + 15bc + 12b^2 + 20c^2
Step 5: Combine the like terms:
(16bc + 15bc) + (12b^2 + 20c^2) = 31bc + 12b^2 + 20c^2
So, the simplified form of (4b+5c)(4c+3b) is 31bc + 12b^2 + 20c^2.