algebra

(4b+5c)(4c+3b)=

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asked by jesus
  1. 16bc+12b(squared)+20c(squared)+15bc

    12b(squared)+ 20c (squared)+ 31bc

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    posted by Ryan
  2. (4b+5c)(4c+3b) = (4b+5c)(3b+4c)

    4b + 5c
    3b + 4c

    Multiplying

    16bc+20C^2
    12b^2+15bc

    = 12b^2+31bc+20c^2

    I hope this makes the process clearer. Thanks for asking.

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    posted by PsyDAG

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