2 nacl (aq) + h2so4 ==> na2so4 (aq) + 2 hci (g)

What is your question?

By the way, lower case where upper case should be used isn't anything. And there is no such animal as hci. HCl perhaps. Not hci.

The given chemical equation represents a reaction between sodium chloride (NaCl) and sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4) and hydrogen chloride gas (HCI).

To balance this chemical equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation. Let's go step by step:

Start with the sodium chloride (NaCl) on the left side. It has one sodium (Na) atom and one chlorine (Cl) atom. On the right side, we have sodium sulfate (Na2SO4), which contains two sodium (Na) atoms. To balance the sodium (Na) atoms, we need to put a coefficient of 2 in front of sodium chloride (NaCl):

2 NaCl (aq) + H2SO4 → Na2SO4 (aq) + 2 HCl (g)

Next, we move on to the chlorine (Cl) atoms. On the left side, we have one chlorine (Cl) atom, and on the right side, we have two hydrogen chloride (HCl) molecules, giving us two chlorine (Cl) atoms. So, the chlorine (Cl) atoms are already balanced.

Now, let's look at the hydrogen (H) atoms. On the left side, we have two hydrogen (H) atoms from the sulfuric acid (H2SO4). On the right side, we have four hydrogen (H) atoms from two hydrogen chloride (HCl) molecules. Since the hydrogen (H) atoms are not balanced, we need to put a coefficient of 2 in front of the hydrogen chloride (HCl):

2 NaCl (aq) + H2SO4 → Na2SO4 (aq) + 2 HCl (g)

Finally, let's check the sulfur (S) and oxygen (O) atoms. On the left side, we have one sulfur (S) atom and four oxygen (O) atoms. On the right side, we have one sulfur (S) atom and four oxygen (O) atoms. So, the sulfur (S) and oxygen (O) atoms are already balanced.

Therefore, the balanced chemical equation is:

2 NaCl (aq) + H2SO4 → Na2SO4 (aq) + 2 HCl (g)