A man is 6 times as old as his son. In 4 years he will be 4 times as old as his son. How old is the father now?
Yaw Dabo is 7 times as old as his daughter. In five years times he will be 4 times as old as his daughter will be then. Find their ages now
To solve this problem, we can set up a system of equations. Let's assume the current age of the son is S, and the current age of the father is F.
According to the problem, the father is 6 times as old as his son:
F = 6S ... (Equation 1)
In 4 years, the father will be 4 times as old as his son:
F + 4 = 4(S + 4) ... (Equation 2)
We can solve this system of equations to find the value of F.
Substituting the value of F in Equation 1 into Equation 2, we get:
6S + 4 = 4(S + 4)
Now, let's simplify and solve for S:
6S + 4 = 4S + 16
2S = 12
S = 6
Now that we have the value of S (the son's age), we can substitute it back into Equation 1 to find F (the father's age):
F = 6S
F = 6(6)
F = 36
Therefore, the father is currently 36 years old.
m = 6s
m+4 = 4(s+4)
so,
6s+4 = 4s+16
2s = 12
s = 6
so, man is 36
check:
40 = 4(6+4)