if the capacitance meter applies a voltage of 3.0 V across the plates and reads a capacitance of 30 pF, what is the charge on the plates?
C = Q/V
30 * 10^-12 = Q/3
Q = 90 * 10^-12 coulombs
To find the charge on the plates of the capacitor, we need to use the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage across the plates.
Given:
Capacitance (C) = 30 pF = 30 × 10^(-12) F
Voltage (V) = 3.0 V
Now, we can substitute the given values into the formula to find the charge (Q).
Q = C × V
Q = (30 × 10^(-12) F) × (3.0 V)
To evaluate this expression, we multiply the values:
Q = (30 × 3.0) × 10^(-12) Coulombs
Q = 90 × 10^(-12) Coulombs
Simplifying:
Q = 9.0 × 10^(-11) Coulombs
Therefore, the charge on the plates of the capacitor is 9.0 × 10^(-11) Coulombs.