C6H14 + Cl2 in UV light
Below are 5 products, say which one cannot be a product, prove this by showing how each of the other products were formed from the equation above.
1-chlorohexane
2-chlorohexane
2,2-dichlorohexane
dodecane
hex-1-ene
I would have to say hex-1-ene.
To determine which product cannot be obtained from the reaction between C6H14 and Cl2 in UV light, we need to examine the various possibilities for product formation.
1. Chlorohexane (C6H13Cl): This is a possible product. It is formed when one H atom from hexane (C6H14) is replaced by a Cl atom.
2. 2-Chlorohexane (C6H13Cl): This product is also possible. It is formed when one of the H atoms attached to the second carbon atom (from the left) in hexane is replaced by a Cl atom.
3. 2,2-Dichlorohexane (C6H12Cl2): This product is possible as well. It is formed when two H atoms, one from each end carbon atom of hexane, are replaced by Cl atoms.
4. Dodecane (C12H26): This product cannot be formed from the given equation because it does not involve the addition or substitution of Cl atoms. It is a completely different compound.
5. Hex-1-ene (C6H12): This product cannot be formed from the given equation either because it requires the removal of H2 from hexane to form a double bond (C=C) between the first and second carbon atoms. The reaction between C6H14 and Cl2 does not involve double bond formation.
Therefore, the product that cannot be obtained from the given equation is dodecane (C12H26).
To determine which product cannot be formed from the reaction between C6H14 (hexane) and Cl2 (chlorine) in UV light, we need to consider the reaction mechanism and the principles of organic chemistry.
When hexane (C6H14) reacts with chlorine (Cl2) in the presence of UV light, a radical substitution reaction called free radical halogenation occurs. This type of reaction is commonly observed when alkanes react with halogens.
The reaction proceeds in three main steps:
1. Initiation: The UV light provides enough energy to break the weak chlorine-chlorine bond (Cl-Cl), producing two chlorine radicals (Cl·).
Cl2 (UV light) → 2 Cl·
2. Propagation: In this step, the chlorine radicals react with hexane to form alkyl radicals, which then react with chlorine to form alkyl halides.
a. Reaction of a chlorine radical with hexane:
Cl· + C6H14 → HCl + C6H13·
b. Reaction of an alkyl radical with chlorine:
C6H13· + Cl2 → C6H13Cl + Cl·
These propagation steps continue until all the reactants are consumed or until termination steps occur.
3. Termination: This step involves the reaction between two radicals to form stable compounds. Multiple termination steps are possible, leading to the formation of various products.
Now, let's analyze each of the options to determine if they are possible products:
1. Chlorohexane (C6H13Cl): This product can be formed by the second propagation step mentioned above.
2. 2-chlorohexane (C6H12Cl2): This product can be formed by the second propagation step if one of the chlorine radicals reacts with the 2nd carbon atom in the hexane chain.
3. 2,2-dichlorohexane (C6H10Cl4): This product can be formed if one chlorine radical reacts with the 2nd carbon atom, and another chlorine radical reacts with the 2nd carbon atom resulting in two Cl substituents.
4. Dodecane (C12H26): This product cannot be formed from the given reaction conditions. It is a different compound entirely, not involving chlorine substitution on the hexane molecule.
5. Hex-1-ene (C6H12): This product cannot be formed from the given reaction conditions. It results from the elimination of HCl from one of the chlorohexane products mentioned earlier.
Therefore, the product that cannot be formed from the reaction between C6H14 and Cl2 in UV light is dodecane (C12H26).