Calculate the molarity of a solution that is prepared by dissolving 23.35g of CaCl2 in a sufficient amount of water to make a 600 mL solution
M = mols/L of solution.
You can calculate mols from mols = grams/ molar mass.
You know molar mass CaCl2 and you know grams. Calculate mols from equation 2, and substitute in equation 1 to calculate molarity.
Post your work if you need more help.
I left a message for you on the H2O2 problem posted earlier.
No, that was rachel.
find molar mass H2O-
23.5x1mol/110.08=0.2134
To calculate the molarity (M) of a solution, you need to know the number of moles of solute (CaCl2) and the volume of the solution in liters (L).
Step 1: Calculate the number of moles of CaCl2.
To determine the number of moles, use the formula:
moles = mass (g) / molar mass (g/mol)
The molar mass of CaCl2 can be found by adding up the atomic masses of calcium (Ca) and chlorine (Cl). The atomic mass of Ca is approximately 40.08 g/mol, and the atomic mass of Cl is approximately 35.45 g/mol.
molar mass of CaCl2 = (40.08 g/mol) + 2 * (35.45 g/mol) = 110.98 g/mol
moles of CaCl2 = 23.35 g / 110.98 g/mol = 0.2101 mol
Step 2: Convert the volume of the solution to liters.
The volume provided is given in milliliters (mL), but we need to convert it to liters (L) before calculating the molarity.
volume (L) = volume (mL) / 1000
volume (L) = 600 mL / 1000 = 0.600 L
Step 3: Calculate the molarity.
Molarity (M) is defined as moles of solute (CaCl2) divided by the volume of the solution in liters (L).
Molarity (M) = moles / volume (L)
Molarity (M) = 0.2101 mol / 0.600 L ≈ 0.350 M
Therefore, the molarity of the solution is approximately 0.350 M.