A shot put ball with mass 5kg is dropped from a height of 1,75m. Ignore air resistance. Calculate the time it takes for the ball to reach the ground
h = Vo*t + 0.5g*t^2 = 1.75 m
0 + 4.9*t^2 = 1.75
Solve for t.
To calculate the time it takes for the shot put ball to reach the ground, we can use the principles of free-fall motion. The equation that relates the height, acceleration due to gravity, and time is given by:
h = (1/2) * g * t^2
Where:
h = Height (1.75m)
g = Acceleration due to gravity (9.8 m/s^2)
t = Time
Rearranging the equation to solve for time (t):
t^2 = (2 * h) / g
Substituting the given values:
t^2 = (2 * 1.75) / 9.8
t^2 = 0.3571
t ≈ √(0.3571)
t ≈ 0.5981 seconds
Therefore, it takes approximately 0.5981 seconds for the shot put ball to reach the ground from a height of 1.75 meters.