Two protons in a nucleus are separated by 8.0×10−15m .
What's the potential energy of the pair?
what is kqq/distance
To calculate the potential energy of two protons in a nucleus, you can use the formula for the electrostatic potential energy:
Potential Energy = (k * (q1 * q2)) / r
Where:
k = Coulomb's constant (9 × 10^9 N m^2/C^2)
q1 and q2 = charges of the protons (each proton has a charge of 1.6 × 10^-19 C)
r = distance between the protons (8.0 × 10^-15 m)
Plugging in these values, we can calculate the potential energy:
Potential Energy = (9 × 10^9 N m^2/C^2 * (1.6 × 10^-19 C * 1.6 × 10^-19 C)) / (8.0 × 10^-15 m)
Simplifying the equation:
Potential Energy = (9 × 10^9 N m^2/C^2 * 2.56 × 10^-38 C^2) / (8.0 × 10^-15 m)
Now, let's calculate the numerical value of the potential energy:
Potential Energy = 2.88 × 10^-5 Joules
Thus, the potential energy of the pair of protons is 2.88 × 10^-5 Joules.