If you know that a 1-kg object weighs 10N, confirm that the acceleration of a 1-kg stone in free fall is 10 m/s2.
To confirm that the acceleration of a 1 kg stone in free fall is 10 m/s^2, we need to apply Newton's second law of motion.
Newton's second law states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, it can be expressed as:
F = m * a,
where F is the force acting on the object, m is the mass of the object, and a is the acceleration.
In this scenario, we know that the object has a mass of 1 kg, and it weighs 10 N. Recall that weight is the force acting on an object due to gravity. So, we can substitute the weight of the object (10 N) for the force (F) in Newton's second law equation:
10 N = 1 kg * a.
Next, we can solve this equation for the acceleration (a):
a = 10 N / 1 kg.
Now, we can calculate the numerical value of the acceleration:
a = 10 m/s^2.
Therefore, we have confirmed that the acceleration of a 1 kg stone in free fall is indeed 10 m/s^2.
f=ma or
a = f/m = 10/1 = ?