The sum of three whole numbers is 7. The second number is 1 more than the twice of the third number. The
sum of first and third number is 3 less than the second number. Find all the three numbers. Thanks
a = first number
b = second number
c = third number
b = 2 c + 1
a + c = b - 3
a + c = ( 2 c + 1 ) - 3
a + c = 2 c - 2
a = 2 c - 2 - c
a = c - 2
a + b + c = 7
c - 2 + 2 c + 1 + c = 7
4 c - 1 = 7
4 c = 7 + 1
4 c = 8 Divide both sides by 4
c = 8 / 4 = 2
a = c - 2 = 2 - 2 = 0
b = 2 c + 1 = 2 * 2 + 1 = 4 + 1 = 5
Numbers :
0 , 5 and 2