A current of 2.10A flows in a wire. How many electrons are flowing past any point in the wire per second?
N=________________________ electrons/s
well, since 1A = 1 Coulomb/sec, just multiply the current (A) by the number of electrons in a Coulomb.
To calculate the number of electrons flowing past any point in the wire per second, we need to use the formula:
N = I / e
Where:
- N is the number of electrons per second
- I is the current in amperes
- e is the elementary charge (1.6 x 10^-19 C)
Given:
I = 2.10 A
e = 1.6 x 10^-19 C
We can now substitute the values into the formula to find N:
N = 2.10 A / (1.6 x 10^-19 C)
Let's calculate this:
N = 1.3125 x 10^19 electrons/s
Therefore, the number of electrons flowing past any point in the wire per second is approximately 1.3125 x 10^19 electrons/s.
To find the number of electrons flowing past any point in the wire per second, we need to use the concept of electric current.
The electric current is the rate of flow of electric charge. It is measured in amperes (A). One ampere is equal to the flow of one coulomb of charge per second.
We know that the current flowing in the wire is 2.10A. To determine the number of electrons flowing per second, we need to calculate the amount of charge represented by this current.
To find the charge, we can use the formula:
Q = I * t
Where:
Q is the charge in coulombs,
I is the current in amperes,
t is the time in seconds.
Since we are finding the number of electrons, we need to convert the charge to the number of electrons. One coulomb of charge is equivalent to approximately 6.242 × 10^18 electrons.
Therefore, the formula to calculate the number of electrons is:
N = Q * (6.242 × 10^18)
We can substitute the given values to find the answer:
N = (2.10A) * t * (6.242 × 10^18)
Since we are interested in the number of electrons per second, t is equal to 1 second.
N = (2.10A) * (1s) * (6.242 × 10^18)
Simplifying the equation:
N = 2.10 * 6.242 × 10^18
N = 13.095 × 10^18
N ≈ 1.31 × 10^19 electrons/s
Therefore, approximately 1.31 × 10^19 electrons flow past any point in the wire per second.
so it would be
N= (2.10A) x (1.602176487×10^−19 C)
= 3.3642 x 10 ^19
Thank you very much Steve!