One gram of nickel has 1.026 × 1022 atoms,
and each nickel atom has 28 electrons.
How many electrons are contained in 6.00
g of nickel? The elemental charge is
1.6 × 10−19 C.
Answer in units of electrons
To calculate the number of electrons in 6.00 g of nickel, you need to use the given information about the number of atoms in 1 g of nickel and the number of electrons in each nickel atom.
First, calculate the number of atoms in 6.00 g of nickel:
Number of atoms in 6.00 g of nickel = (1.026 × 10^22 atoms/g) × (6.00 g)
= 6.156 × 10^22 atoms
Now, calculate the number of electrons in 6.00 g of nickel:
Number of electrons in 6.00 g of nickel = (Number of atoms in 6.00 g of nickel) × (Number of electrons per atom)
= (6.156 × 10^22 atoms) × (28 electrons/atom)
= 1.721 × 10^24 electrons
Therefore, there are 1.721 × 10^24 electrons contained in 6.00 g of nickel.
To answer this question, we need to use the given information:
1 gram of nickel has 1.026 × 10^22 atoms.
Each nickel atom has 28 electrons.
First, let's find out how many atoms are present in 6.00 g of nickel:
Number of atoms = Number of atoms in 1 gram x Mass of nickel (in grams)
Number of atoms = (1.026 × 10^22 atoms/g) x 6.00 g
Multiply these values together to get the number of atoms in 6.00 g of nickel.
Next, we need to find the total number of electrons in 6.00 g of nickel:
Number of electrons = Number of atoms x Number of electrons per atom
Number of electrons = (Number of atoms) x 28 electrons/atom
Multiply the number of atoms from the previous step by 28 to find the total number of electrons.
Finally, we can convert the total number of electrons into units of electrons by multiplying it with the elementary charge of an electron (1.6 × 10^-19 C).
The final answer will be in units of electrons, which represents the total number of electrons in 6.00 g of nickel.