How many grams of MG in 1.5 g of chloride ions in MGCL2
It's Mg and MgCl2.
1.5 g Cl x (molar mass Mg/2*atomic mass Cl) = ?
To determine the number of grams of magnesium (Mg) in 1.5 g of chloride ions (Cl-) in MgCl2, we need to consider the molar mass and the molar ratio in the compound.
Here's the step-by-step process to solve the problem:
1. Find the molar mass of MgCl2:
- The atomic mass of magnesium (Mg) is approximately 24.31 g/mol.
- The atomic mass of chlorine (Cl) is approximately 35.45 g/mol.
- Since there are two chloride ions in MgCl2, multiply the atomic mass of chlorine by 2.
- Molar mass of MgCl2 = 24.31 g/mol + (35.45 g/mol x 2) = 95.21 g/mol
2. Calculate the molar ratio between chloride ions and magnesium:
- In MgCl2, there is one magnesium ion (Mg2+) for every two chloride ions (2Cl-).
- The molar ratio of MgCl2 is 1:2 (Mg:Cl-).
3. Determine the number of moles of chloride ions:
- Given that the mass of chloride ions is 1.5 g, divide this by the molar mass of chloride (Cl), which is approximately 35.45 g/mol:
- Number of moles of Cl- ions = 1.5 g / 35.45 g/mol = 0.0423 mol
4. Calculate the number of moles of magnesium:
- From the molar ratio, we know that for every two chloride ions, there is one magnesium ion.
- Therefore, the number of moles of magnesium is half the number of moles of chloride ions.
- Number of moles of Mg = 0.0423 mol / 2 = 0.0211 mol
5. Convert moles of magnesium to grams:
- Multiply the number of moles of magnesium by the molar mass of magnesium (24.31 g/mol):
- Mass of Mg = 0.0211 mol x 24.31 g/mol = 0.513 g
Therefore, there are approximately 0.513 grams (g) of magnesium (Mg) in 1.5 g of chloride ions (Cl-) in MgCl2.