three computers were on sale model E computer was priced at 1/3 the price model C and model P was priced at 1/2 the price of model E on business bought one of each type of computers on sale and paid a total $1800
e = c/3
p = e/2
e+c+p = 1800
c/3 + c + c/6 = 1800
3c/2 = 1800
c=1200
e=400
p=200
To solve this problem, let's first assign variables to the prices of each computer. Let:
- Price of Model E computer be "E"
- Price of Model C computer be "C"
- Price of Model P computer be "P"
From the given information:
- Model E computer is priced at 1/3 the price of Model C: E = (1/3)C
- Model P computer is priced at 1/2 the price of Model E: P = (1/2)E
We know that the business bought one of each type of computer, so we can sum up the total cost as follows:
E + C + P = $1800
Now, let's substitute the values of E and P using the given information:
E + C + (1/2)E = $1800
Combine like terms:
(1 + 1/2)E + C = $1800
(3/2)E + C = $1800
Since we have two variables and only one equation, we need another equation to solve for both E and C. However, there isn't enough information provided to do so. We can only express E in terms of C and find the relationship between their values.
Therefore, the information given is not sufficient to determine the exact prices of Model E, Model C, and Model P.