A rectangular garden is 6m longer than it is wide. Find the dimensions of the garden if its area is 520m"?

520 = 20*26

To find the dimensions of the garden, we can set up an equation using the given information.

Let's assume the width of the garden is "x" meters.
According to the problem, the length of the garden is 6 meters longer than its width. Therefore, the length would be "x + 6" meters.

The area of a rectangle can be calculated by multiplying its length and width. In this case, the area is given as 520 square meters.

So, the equation becomes:
x * (x + 6) = 520

To solve this equation, we need to find the values of x that satisfy this equation.

Expanding the equation, we get:
x^2 + 6x = 520

Rearranging the equation to get a quadratic equation in standard form, we have:
x^2 + 6x - 520 = 0

Now, we can factor this quadratic equation or use the quadratic formula to find the values of x.

After solving this equation, we find that the two possible values of x are -26 and 20.

Since the width of a garden cannot be negative, we discard the -26 value.

Therefore, the width of the garden is 20 meters.

To find the length, we substitute this value back into the expression x + 6:
20 + 6 = 26

So, the length of the garden is 26 meters.

Therefore, the dimensions of the garden are 20 meters (width) and 26 meters (length).