ten dipoles, each consisting of two charges +- 19 uC, are located within a spherical surface, the radius of which is 2 mm. What is the flux density through the sphere
i got 4.1*10^6 N-m^2/C ???????????
To find the flux density through the sphere, we can use Gauss' law, which states that the total electric flux through a closed surface is equal to the net charge enclosed divided by the permittivity of free space (ε₀).
First, let's calculate the net charge enclosed by the spherical surface. Since there are ten dipoles, each dipole consisting of two charges (+19 μC and -19 μC), the total charge enclosed by the sphere is:
Q = 10 * (19 μC + (-19 μC)) = 0
Since the net charge enclosed is zero, the electric flux through the sphere is also zero. Therefore, the flux density through the sphere is 0 N·m²/C.