If the field strength is E = 9 V/m a distance of 1 m from the charge, what is the field strength E a distance of 3 m from the charge?
To find the field strength at a distance of 3m from the charge, we can use Coulomb's Law equation, which states that the magnitude of electric field strength (E) is directly proportional to the magnitude of the electric charge (Q) and inversely proportional to the square of the distance (r) between them.
Mathematically, the equation is:
E = k * (Q / r^2)
In this equation, k is the electrostatic constant, approximately equal to 8.99 x 10^9 Nm^2/C^2.
Given that the electric field strength E is 9 V/m at a distance of 1m from the charge, we can rewrite the equation as:
9 = k * (Q / 1^2) --> Equation 1
To find the field strength E at a distance of 3m from the charge, we need to solve for Q using Equation 1 and then substitute the value of Q into Equation 2.
First, let's find Q:
Q = 9 * 1^2 / k
= 9 / k
Now, substitute Q into Equation 2 to find the field strength E at a distance of 3m:
E = k * (Q / 3^2)
= k * (9 / k) / 9
= 1 V/m
Therefore, the field strength E at a distance of 3m from the charge is equal to 1 V/m.