A small washer is taped to a golf ball and the ball is hung from an electromagnet. When a trigger is activated the electromagnet will shut off and the golf ball will fall through a height of 75 cm to land on a time of flight pad. Determine the amount of time it will take for the ball to impact the time of fight pad once the trigger is activated. (Ignore air resistance)
h=1/2 g t^2
t=sqrt (2*.75/9.8) seconds
Thanks for the help. It is much appreciated!
You are welcome.
Why did the golf ball go to therapy? To work on its flight issues! Now, let's calculate that time of flight for you.
To determine the time it takes for the ball to impact the time of flight pad, we can use the equation:
t = √(2h/g)
Where:
t is the time of flight,
h is the height the ball falls through (75 cm or 0.75 m in our case), and
g is the acceleration due to gravity (approximately 9.8 m/s²).
Plugging in the values, we have:
t = √(2 * 0.75 / 9.8) ≈ √(0.153) ≈ 0.39 seconds.
So, it will take the golf ball approximately 0.39 seconds to impact the time of flight pad once the trigger is activated. Keep an eye out for any banana peels on the way!
To determine the amount of time it will take for the golf ball to impact the time of flight pad, we can use the principles of free fall and the equations of motion.
The equation that relates the height of the fall to the time it takes for an object to fall is given by:
h = (1/2) * g * t^2
Where:
h is the height (75 cm or 0.75 m)
g is the acceleration due to gravity (approximately 9.8 m/s^2)
t is the time
Rearranging the equation to solve for time t:
t = sqrt((2 * h) / g)
Substituting the given values into the equation, we get:
t = sqrt((2 * 0.75) / 9.8)
Calculating the expression, we find:
t ≈ 0.387 seconds
Therefore, it will take approximately 0.387 seconds for the golf ball to impact the time of flight pad once the trigger is activated.
.75 = (1/2)9.8*t^2
t^2 = .153
t = .391 second