A 750 kg rocket accelerates straight upward from the ground at 60 m/s2. What is the force (thrust) provided by the engine?
with a gravitational pull of 10 m/s2 down
force=mg+ma
To find the force (thrust) provided by the engine, we need to use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, the mass of the rocket is given as 750 kg, and the acceleration is 60 m/s^2 in the upward direction. However, since the rocket is also experiencing a gravitational pull downward, we need to account for it.
Gravity exerts a force on the rocket, which can be calculated using the formula: force = mass x acceleration due to gravity. In this scenario, the acceleration due to gravity is 10 m/s^2.
First, we calculate the gravitational force acting on the rocket:
Force due to gravity = mass x acceleration due to gravity
Force due to gravity = 750 kg x 10 m/s^2
Force due to gravity = 7500 N (Newtons) downwards
Now, we can calculate the net force acting on the rocket. The net force is the vector sum of the engine thrust force and the force due to gravity.
Since the rocket is accelerating upward, the net force can be calculated as:
Net force = Thrust force - Force due to gravity
Substituting the values we have:
Net force = Thrust force - 7500 N
Since we know that the net force is equal to mass times acceleration:
Net force = mass x acceleration
Thrust force - 7500 N = 750 kg x 60 m/s^2
Solving for the thrust force:
Thrust force = 750 kg x 60 m/s^2 + 7500 N
Thrust force = 45000 N + 7500 N
Thrust force = 52500 N
Therefore, the force (thrust) provided by the engine is 52500 Newtons.