The ractangle given has a perimeter of 14 units. Find the value(s) of x by factoring a quadriatic equation.
x= 12/(x+1)
y= 6/ (4-x)
If anyone can help me that would be awesome, thanks a bunch.
I can only give you an example : for example x2 - x -6 = 0
solution
x2 - 6 = 0
(x + 2 )(X + 3 ) = 0
X + 2 = 0 X= -2
X - 3 = 0 X=3
THE EQUATION HAS A TWO SOLUTION -2 AND 3
thanks ne ways.
I can only give you an example : for example x2 - x -6 = 0
solution
x2 - 6 = 0
(x + 2 )(X + 3 ) = 0
X + 2 = 0 X= -2
X - 3 = 0 X=3
THE EQUATION HAS A TWO SOLUTION -2 AND 3
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To find the value(s) of x, we need to set up two separate equations based on the given information:
1) x = 12/(x+1)
2) y = 6/(4-x)
Let's start by simplifying equation 1:
x(x+1) = 12
By distributing, we get:
x^2 + x = 12
To solve this quadratic equation by factoring, we need to rewrite it in the form of (x+a)(x+b) = 0.
In this case, a and b are the values that, when multiplied, give us 12, and when added, give us 1.
We need to find two numbers that satisfy these conditions. In this case, the numbers are 3 and 4.
So, we can rewrite the equation as:
(x+3)(x+4) = 0
Now, we set each factor equal to zero:
x + 3 = 0 --> x = -3
x + 4 = 0 --> x = -4
Therefore, the values of x that satisfy equation 1 are -3 and -4.
Now, let's move on to equation 2:
y = 6/(4-x)
To solve for x in this equation, we need to isolate it.
Start by multiplying both sides of the equation by (4-x):
y(4-x) = 6
Now, divide both sides by y:
4 - x = 6/y
Next, let's isolate x by subtracting 4 from both sides:
-x = 6/y - 4
Finally, multiply both sides by -1 to solve for x:
x = -6/y + 4
Thus, the value of x that satisfies equation 2 is -6/y + 4.
To summarize, the values of x that satisfy both equations are -3, -4, and -6/y + 4.