a 50-N force is directed at an angle of 50 degrees above the horizontal. resolve this force into vertical and horizontal components.

50N[50o]

X = 50*cos50
Y = 50*sin50

To resolve a force into its vertical and horizontal components, we can use trigonometry. Given a force of 50 N at an angle of 50 degrees above the horizontal, we can find the vertical and horizontal components using the following formulas:

Vertical Component (Fv) = Force (F) * sin(angle)
Horizontal Component (Fh) = Force (F) * cos(angle)

Let's calculate the components step-by-step:

Vertical Component (Fv) = 50 N * sin(50 degrees)
Horizontal Component (Fh) = 50 N * cos(50 degrees)

Calculating each component:

Vertical Component (Fv) = 50 N * 0.766 (rounded to 3 decimal places)
Vertical Component (Fv) ≈ 38.300 N

Horizontal Component (Fh) = 50 N * 0.643 (rounded to 3 decimal places)
Horizontal Component (Fh) ≈ 32.150 N

Therefore, the vertical component of the force is approximately 38.300 N, and the horizontal component is approximately 32.150 N.

To resolve a force into its vertical and horizontal components, you can use trigonometry. Here's how to do it:

1. Draw a diagram: Draw a coordinate system with the x-axis representing the horizontal direction and the y-axis representing the vertical direction. Mark the angle (in this case, 50 degrees) between the force and the horizontal direction.

2. Identify the given values: The given force is 50 N, and the angle is 50 degrees.

3. Calculate the horizontal component: To find the horizontal component (F_horizontal), use the formula F_horizontal = F * cosθ, where F is the magnitude of the force and θ is the angle between the force and the horizontal direction.
F_horizontal = 50 N * cos(50 degrees)
F_horizontal ≈ 50 N * 0.6428
F_horizontal ≈ 32.14 N

4. Calculate the vertical component: To find the vertical component (F_vertical), use the formula F_vertical = F * sinθ, where F is the magnitude of the force and θ is the angle between the force and the horizontal direction.
F_vertical = 50 N * sin(50 degrees)
F_vertical ≈ 50 N * 0.7660
F_vertical ≈ 38.30 N

Therefore, the resolved force is approximately 32.14 N in the horizontal direction and 38.30 N in the vertical direction.