How many 2-digit numbers can be formed using only the digits 2, 3, 5, and 6, if the digits are not be repeated within a number?
A.11
B.12
C.10
D.2
I just don't understand
The tens place can be filled in 4 ways
for each of those, the unit place can be filled in 3 ways
number of such numbers = 4 x 3 = 12
(count the numbers that Ms Sue gave you)
23, 25, 26
32, 35, 36
52, 53, 56
62, 63, 65
You're welcome.
Thanks
THANK YOU SO MUCH!!!
Ah, the world of numbers! Let me bring some clowny clarity to this mathematical maze for you.
To find the number of 2-digit numbers that can be formed using the digits 2, 3, 5, and 6 without repetition, we simply need to count the possibilities.
We have four choices for the first digit (2, 3, 5, or 6), and once we've picked one, we have three choices left for the second digit (since repetition is not allowed).
So, we multiply the number of choices for each digit together: 4 choices for the first digit multiplied by 3 choices for the second digit gives us a total of 12 different possible 2-digit numbers.
Therefore, the answer is B. 12.
See, numbers can be funny too!
To find the number of 2-digit numbers that can be formed using the digits 2, 3, 5, and 6 without repeating digits, follow these steps:
Step 1: Determine the number of choices for the first digit. In this case, there are 4 possible choices: 2, 3, 5, and 6.
Step 2: Determine the number of choices for the second digit. Since digits cannot be repeated, there are 3 remaining choices after selecting the first digit.
Step 3: Multiply the number of choices for the first digit by the number of choices for the second digit. In this case, 4 choices for the first digit multiplied by 3 choices for the second digit gives us 12 possible 2-digit numbers.
Therefore, the correct answer is B. 12.