Write the equation for the reaction of each of the following with water.

a) HCl
b) CH3COOH
c) NaOH
d) NH3

Are these correct?

a. HCl (aq) + H2O (l) --> H3O+ (aq) + Cl- (aq)

b. CH3COOH (aq) + H2O (l) --> CH3COO- (aq) + H3O+ (aq)

c. NaOH (aq) + H2O (l) --> Na+ + OH- + H2O
[I don't know how I would write it...]

d. NH3 (aq) + H2O (l) --> NH4+ (aq) + OH- (aq)

They are correct.

Yes, your equations are correct for the reactions of each substance with water.

Here's how you can determine the equations:

a) HCl: When HCl (hydrochloric acid) reacts with water, it dissociates into H3O+ (hydronium ion) and Cl- (chloride ion). So, the equation would be:

HCl(aq) + H2O(l) → H3O+(aq) + Cl-(aq)

b) CH3COOH: Acetic acid (CH3COOH) also dissociates in water. It forms CH3COO- (acetate ion) and H3O+ (hydronium ion). The equation is:

CH3COOH(aq) + H2O(l) → CH3COO-(aq) + H3O+(aq)

c) NaOH: Sodium hydroxide (NaOH) is a strong base, so it dissociates completely in water into Na+ (sodium ion) and OH- (hydroxide ion). The equation can be written as:

NaOH(aq) + H2O(l) → Na+(aq) + OH-(aq)

d) NH3: Ammonia (NH3) is a weak base. When it reacts with water, it accepts a proton (H+) to form the ammonium ion (NH4+) and the hydroxide ion (OH-). The equation is:

NH3(aq) + H2O(l) → NH4+(aq) + OH-(aq)

Remember, it's important to balance the charges and ensure mass conservation when writing chemical equations.