Chemistry

What mass in grams of a 0.500 m(molal) solution of sodium acetate, CH3CO2Na, in water would you use to obtain 0.200mol of sodium acetate?

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  1. 0.5 m solution = 0.5 mol solute/kg solvent.
    mol = g/molar mass and molar mass = about 82 g/mol.
    0.5 mol = 1/2*82 = about 41
    So 41g CH3COONa in 1 kg H2O = total mass of 1041g.

    You want 0.2 mol CH3COONa so
    1041g x (0.2/0.5) = ? mass solution

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  2. 416 grams

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  3. 0.200 mol ch3coona are in 1041/0.5×0.200
    = 416.4g solutiob

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