In an English class last semester, Foofy earned a 76 1X 5 85, SX 5 10). Her
friend, Bubbles, in a different class, earned a 60 1X 5 50, SX 5 4). Should Foofy be bragging about how much better she did? Why?
For the data in question 13, find the raw scores that correspond to the following: (a) z 5 11.22; (b) z 5 20.48.
Same problem.
To determine whether Foofy should be bragging about how much better she did compared to Bubbles, we need to compare their scores using the information given. Let's break down the scores:
Foofy's score: 76 1X 5 85, SX 5 10
Bubbles' score: 60 1X 5 50, SX 5 4
From the given information, we can see that both Foofy and Bubbles received two different sets of scores. In each set, there are two numbers separated by "1X" and "SX."
1X represents the average score, while SX represents the standard deviation. The average score indicates the overall performance, and the standard deviation describes the spread or variation in the scores.
Foofy's average score in her English class is given as 76, and Bubbles' average score in a different class is given as 60. Foofy has a higher average score than Bubbles, indicating that she performed better on average.
However, to fully evaluate their performances, we also need to consider the standard deviation. Foofy's standard deviation is given as 10, while Bubbles' standard deviation is given as 4. The lower the standard deviation, the less variation there is between the scores, suggesting more consistency.
In this case, Bubbles has a lower standard deviation than Foofy, indicating that her scores are more consistent. Foofy, on the other hand, has a higher standard deviation, indicating more variability in her scores.
Therefore, even though Foofy has a higher average score, Bubbles' scores are more consistent. Whether Foofy should brag about how much better she did depends on whether she values consistency or overall performance more.