Height of children in kindergarten described by normal mode with mean 39.2 inches and standard deviation of 1.9 inches.

What percent of children can expect to be less than 38 inches tall?

enter your data into

http://davidmlane.com/hyperstat/z_table.html

click on "below"
you should get 0.2638
so 26.38 % are less than 38 inches tall

To find the percentage of children who can expect to be less than 38 inches tall, we can use the Z-score formula and the standard normal distribution table.

Step 1: Calculate the Z-score.
The Z-score formula is given by:
Z = (X - μ) / σ

Where:
X = 38 inches (the height we want to find the percentage for)
μ = mean height = 39.2 inches
σ = standard deviation = 1.9 inches

Substituting the given values, we get:
Z = (38 - 39.2) / 1.9
Z ≈ -0.63

Step 2: Use the Z-score to find the percentage.
Using the standard normal distribution table or a calculator with a cumulative distribution function (CDF), we can find the percentage corresponding to the Z-score of -0.63. This will give us the percentage of children below 38 inches tall.

Looking up the Z-score of -0.63 in the standard normal distribution table, we find that the corresponding percentage is 26.1%.

Therefore, approximately 26.1% of children can expect to be less than 38 inches tall in kindergarten.

To find the percent of children who can expect to be less than 38 inches tall, we can use the concept of z-scores and the standard normal distribution.

Step 1: Calculate the z-score
The z-score is a measure of how many standard deviations a particular value is from the mean. It is calculated using the formula:

z = (x - μ) / σ

Where:
x = the value (38 inches in this case),
μ = the mean of the distribution (39.2 inches),
σ = the standard deviation of the distribution (1.9 inches).

Plugging in the values, we get:

z = (38 - 39.2) / 1.9
z ≈ -0.632

Step 2: Find the percentile from the z-score
The z-score can be used to find the percentile from the standard normal distribution table or by using a calculator or online tool. The percentile represents the percentage of data that falls below a given value.

Using a normal distribution table or an online calculator, we find that the area to the left of a z-score of -0.632 (i.e., below -0.632) is approximately 0.2659.

Step 3: Convert the percentile to a percentage
To get the percentage, we multiply the decimal value by 100:

0.2659 * 100 ≈ 26.59%

Therefore, approximately 26.59% of children can expect to be less than 38 inches tall.