Two times the smallest of three consecutive odd integers is one less than the largest integer. Find the integers
if the integers are x-2,x,x+2, then
2(x-2) = x+2-1
2x-4 = x+1
x = 5
so the numbers are 3,5,7
thanks
The peremeter of rectangle 7less than the 5 times the width
To solve this problem, let's represent the three consecutive odd integers using variables. Let's call the smallest odd integer "n", the middle odd integer "n + 2", and the largest odd integer "n + 4".
According to the given information, two times the smallest integer is one less than the largest integer. We can express this in an equation:
2n = (n + 4) - 1
Now, let's solve this equation to find the value of "n":
2n = n + 3 (combine like terms)
n = 3 (subtract n from both sides)
So, the smallest odd integer is 3. The middle odd integer is 3 + 2 = 5, and the largest odd integer is 3 + 4 = 7.
Therefore, the three consecutive odd integers are 3, 5, and 7.