Chemistry

What is the maximum height achieved if a 0.800 kg mass is thrown straight upward with an initial speed of 40.0 m·s–1? Ignore the effect of air resistance.

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  1. Thats what it looks like.. but im taking chem. in college and have never had a physics course, im really lost.

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  2. My physics is quite rusty but I believe that would be
    V^2 = Vo^2 + 2ax
    V^2 will be zero at the top since eventually the pull of gravity will stop the balls upward flight.
    0 = (40 m/s)^2 + 2*(-9.8)*x
    Solve for x = distance in meters.

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  3. alright, thanks lol

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